Answer: 0.11g/mol
Explanation: 1mole of any gas contains 22.4L at stp.
Xmol of the gas will contain 255L i.e
Xmol of the gas = 255/22.4 = 11.38moles
recall
n = Mass conc. / molar Mass
Molar Mass = Mass conc. / n
Molar Mass = 1.25/11.38 = 0.11g/mol
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