Question

A piece of machinery loses $20 in value every month. Its value after m months of service is $1475. Which is the rate of change in this situation?

Answer 1

Answer:
`Rate\ of\ change=20`

Explanation:

The Slope-Intercept form of an equation of a line is the following:

`y=mx+b`

Where "m" is the slope of the line and "b" is the y-intercept.

By definition, the slope is:

`m=(change\ in\ y)/(change\ in\ x)`

Since the rate of change shows how a quantity changes in relation to another quantity, this is:

`Rate\ of\ change=m=(change\ in\ y)/(change\ in\ x)`

You must remember that It is a constant.

According to the information given in the exercise, a piece of the machinery loses $20 in value every month (Notice that this is constant) and its value after "m" months of service is $1,475.

Therefore, you can identify that:

`m=20`

Then, you get that the rate of change in this situation is:

`Rate\ of\ change=m=20`