Answer:
The probability that both balls are white = 11/15
Step-by-step explanation:
pr = n(possible outcome)/n(total outcome)
Where pr = probability, n = number
If two balls are selected are random without replacement
pr(both balls are white) = pr(1)×pr(2)................ Equation
pr(1) = probability of picking the first white ball, pr(2) = probability of picking the second with ball
pr(1) = n(possible outcome)/n(total outcome)
n(possible outcome) = 4
n(total outcome) = 10
pr(1) = 4/10 = 2/5
After the first pick without replacement, the total number of ball will decrease.
pr(2) = n(possible outcome)/n(total outcome)
n(possible outcome) = 3
n(total outcome) = 9
pr(2) = 3/9 = 1/3
Therefore,
pr(both balls are white) =(2/5) + (1/3)
Adding both fraction,
pr(both balls are white) = (6+5)/15
pr(both balls are white) = 11/15.
Thus the probability that both balls are white = 11/15