Question

63.55 169.88 187.57 107.87

Cu + 2AgNO3 \longrightarrow⟶ Cu(NO3)2 + 2Ag

How many grams of Cu are required to produce 3.98 g of Ag?

Answer 1

1.2 g

Step-by-step explanation:

Data Given:

mass of Ag = 3.98 g

mass of Cu = ?

Reaction Given:

Cu + 2AgNO₃ --------→ Cu(NO₃)₂ + 2Ag

Solution:

To solve this problem we have to look at the reaction

Reaction:

Cu + 2AgNO₃ --------→ Cu(NO₃)₂ + 2Ag

1 mol 2 mol

from reaction we come to know that 1 mole of Cu give 2 moles of Ag

Now Convert moles to mass

Molar mass of Cu = 63.5 g/mol

Molar mass of Ag = 107.9 g/mol

So,

Cu + 2 AgNO₃ --------→ Cu(NO₃)₂ + 2Ag

1 mol (63.5 g/mol) 2 mol ( 107.9g/mol)

63.5 g 215.8 g

So if we look at the reaction 63.5 g of Cu gives 215.8 g of Ag, then how many g of Cu will be Produce by 3.98 g of Ag

For this apply unity formula

63.5 g of Cu ≅ 215.8 g of Ag

X g of Cu ≅ 3.98 g of Ag

By Doing cross multiplication

mass of Cu = 3.98 g x 63.6 g / 215 g

mass of Cu = 1.2 g

1.2 g of Cu will produce 3.98 g of Ag