Question

Help me choose which answer!

Answer 1

The time period =
`(\pi)/(2)`

Step-by-step explanation:

Let's assume a pendulum of length l and time period T.

Then the equation for the time period, T =
`2\pi \sqrt{(l)/(g) }`

Here g = acceleration due to gravity = 9.8 m/
`s^(2)`

Here we are given a simple pendulum of length 2.45 m.

Substitute this value of length in the given equation,

T =
`2\pi \sqrt{(l)/(g) }`

=
`2\pi \sqrt{(2.45)/(9.8)}`

=
`(\pi )/(2)`

Hence the time period =
`(\pi)/(2)`