Question

Someone plzzz help with this numbers 1-13 and show work I’ll give extra points plzzz

Answer 1

1. Look at the attached image

2. Look at the attached image

3. Mass Number

4. Proton =14

5. Proton = electron = 82 , Neutron = 125

6. Atomic number = 28

7. neutron = 197

8. More by neutron = 2

9. Charge on Al = Zero(Neutral)

10 .Valance electron = 6

11.charge on S = -2

12. Valence electron = 1

13. charge on Na = +1

Step-by-step explanation:

Atomic Number = Total number of protons present in the nucleus of the atom.

Atomic number = proton

Mass Number = Total number of proton and neutron present in the nucleus of the atom.

Mass number = number of proton + neutron

Symbolic representation :

`_(A)^(Z)\textrm{X}`

A = mass number = proton + neutron

Z = atomic number = proton

X = element

Charged Species = Ions = These are formed by loss of gain of electron by the atom .

Negative charge = Gain electron

Positive Charge = Loss of electron

Que 1.

In the table :

Symbol = From periodic table you have to know the symbols of element and their atomic number.

Atomic number = Periodic table

Proton = Atomic number : Proton and atomic number are same

Electron count :

For neutral element : Number of proton = Number of electron

E.g

Electron in Fe = 26 = proton number

Electron in K = 19 = proton number

For Negative Charged specied : Charge + Proton

For Positive Charged specied : Proton - Charge

For I-

Charge = 1

Electron = Proton + charge = 53 + 1 = 54

Que 2.

`_(14)^(7)\textrm{N}^(3-)`

Proton = Z = 7

Neutron = A - Z = 14 - 7 = 7

electron = proton + charge = 7 + 3 = 10

`_(112)^(48)\textrm{Cd}^(2+)`

Proton = Z = 48

Neutron = A - Z = 112 - 48 = 64

electron = proton + charge = 48 -2 = 46

`_(64)^(29)\textrm{Cu}`

Proton = Z = 29

Neutron = A - Z = 64 -29 =35

electron = proton = 35 (no charge)

`_(119)^(50)\textrm{Sn}^(4+)`

Proton = Z = 50

Neutron = A - Z = 119-50 = 69

electron = proton = 50 - 4 = 46

Que 3.

The Number 79 - In Se-79 represent the (Mass Number)

Q4

Protons present in Si - 28 = 14 ( atomic nuber of Si = 14)

Q5.

The Number of subatomic particles in 207 Pb =

Proton = 82

neutron =207-82 =125

Electron = 82

Q6.

Atomic number for an element with 31 neutron and mass number 59 = 28

Q7. The mass number for gold having 118 neuton is = 197

Q8 . more neutron are there in Br-80 than Br-78 (80 - 78) = 2

Q9 . Charge on Al atom = Zero

Q 10. Valance electron in S = 6

Valancy = total electron present in outermost shell

Its atomic number = 16

Electronic Configuration = 2 + 8 + 6 (=16)

It has 6 electron in outermost shell

Q11. Charge on S = -2

To complete its (8 electron in outermost shell) octet ,S gains 2 electron . Hence it get -2 charge

Q12. Valance electron in Na = 1

Its atomic number = 11

Electronic Configuration = 2 + 8 + 1 (=11)

It has 1 electron in outermost shell

Q13. Charge on Na = +1

To complete its (8 electron in outermost shell) octet ,Na loses 1 electron . Hence it get +1 charge