71.7k views
21 votes
PLEASE HELP I'M DESPERATE

Examine the following diagram, where AP is secant to the circle at points A and B, and CP is secant to the circle at points C and D. The lines intersect outside the circle at point P. What is the length of PD?

11

7

12

9

PLEASE HELP I'M DESPERATE Examine the following diagram, where AP is secant to the-example-1
User Afsane
by
5.3k points

1 Answer

5 votes

Answer:

Explanation:

The formula for 2 secants coming out of a common point is a proportion

The formula in this case, is

PA*PB = CD * PC

Givens

PB = 10

PA = 8 + 10 = 18

PD = X

PC = X + 20

Solution

10*18 = x * (x + 20) Cross Multiply

180 = x^2 + 20x Remove the Brackets

180 -180 = x^2 + 20x -180 Subtract 180 from both sides.

0 = x^2 +20x - 180 Combine

This factors into something not in your answer choices or even close rounded.

Make sure you have the right diagram for the right question.

User PMerlet
by
5.4k points