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What is an equation of the line that is perpendicular to y+1=-3(x-5)

User EdwynZN
by
7.3k points

1 Answer

4 votes

Answer: 3y - x - 42 = 0

Step-by-step explanation:

The equation y + 1 = -3(x - 5)

Now expand the expression by opening the brackets

y + 1 = -3x + 15

Recall,

Equation of line , y = mx + c , where m = slope

rearranging the equation above in order to determine the ( m)

y = -3x -1 + 15

y = -3x + 14

Recall again condition for perpendicularity

m₁m₂ = -1

From the equation given, m₁ = -3, therefore , to get m₂

-3 x m₂ = -1

-3m₂ = -1

Therefore m₂ = -1/-3

m₂ = 1/3

Now , to find the equation of the second line parallel to the first one,

Just replaced the -3 in the equation above by m₂ = 1/3 in

y = -3x + 14

y = x/3 + 14

Now , multiply both the RHS and LHS of the equation by 3, to make it a linear.

3y = x + 3 x 14

3y = x + 42

3y - x - 42 =0

User Nahida
by
6.2k points
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