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Solve the equation, keeping the value for x as an improper fraction.

Solve the equation, keeping the value for x as an improper fraction.-example-1
User Hugmungus
by
7.4k points

1 Answer

2 votes

Answer:

x = 30/7

Explanation:

Given:
$ (2)/(3)x = -(1)/(2)x + 5 $

Adding
$ (1)/(2)x $ on both sides, we get:


$ (2)/(3)x + (1)/(2)x = 5 $

Taking x common outside, we get:


$  \bigg( (2)/(3) + (1)/(2) \bigg)x  = 5 $

Taking LCM, we get:


$ \bigg( (4 + 3)/(6) \bigg ) x = 5 $


$ (7)/(6)x = 5 $

Multiplying by
$ (7)/(6) $ to determine the value of x, we get:


$ x = (6)/(7) . 5 $

Therefore,
$ x = (30)/(7) $ which is the required answer.

User Thiago Mata
by
8.0k points

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