Question

What is the equation of the following line? Be sure to scroll down first to see

all answer options.

I put the picture

Answer 1

`\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{0}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{0}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-3)}}}\implies \cfrac{-1}{0+3}\implies -\cfrac{1}{3}`

`\bf \begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{-\cfrac{1}{3}}[x-\stackrel{x_1}{(-3)}]\implies y-1=-\cfrac{1}{3}(x+3) \\\\\\ y-1=-\cfrac{1}{3}x-1\implies y=-\cfrac{1}{3}x`