177k views
1 vote
Area of a triangle whose vertices are (3,3) (3,-1) (-2,-5)​

User Riyad
by
4.1k points

2 Answers

2 votes

Answer:

16cm^2

Explanation:

User Ken Yao
by
4.8k points
1 vote

Answer:

10 square units

Explanation:

The first two vertices are on the line x=3, separated by 3-(-1) = 4 units in the y-direction.

The third vertex has an x-value that is 3-(-2) = 5 units away from the "base" on the line x=3. So, the "height" of the triangle is 5, and its base length is 4.

The area is ...

A = (1/2)bh = (1/2)(4)(5) = 10 . . . . square units

Area of a triangle whose vertices are (3,3) (3,-1) (-2,-5)​-example-1
User YanMeng
by
4.4k points