Answer:
Explanation:
3x + 5y = 11
5y = - 3x + 11
y = -3x/5 + 11/5
Slope = -3/5
The required line is parallel to this line, So required line's slope= -3/5
(15,4)
y-y1 = m(x-x1)
y - 4 = -3/5 (x - 15)
y -4 = -3x/5 + 15*3/5
y - 4 = -3x/5 + 9
y = -3x/5 + 9 +4
y = -3x/5 + 13