Question

Which equation represents a parabola that opens upward, has a minimum value of 3, and has an axis of symmetry at x= 3?

R2) = (x + 3)2 - 6
1 x) = (x + 3)2 + 3
2x) = (x - 3)2 - 6
OD. 10) = (x - 3y2 +3
Why

Answer 1

Explanation:

Hope this Helps ;)

Answer 2

`y=(x-3)^2+3`

Explanation:

The correct question is

Which equation represents a parabola that opens upward, has a minimum value of y=3, and has an axis of symmetry at x= 3?

Verify each case

case 1) we have

`y=(x+3)^2-6`

This a vertical parabola open upward (the leading coefficient is positive)---> is ok

The vertex represent a minimum ---> is ok

The vertex is the point (-3,-6)

The minimum value of y=-6 ----> is not ok

The axis of symmetry is x=-3 ----> is not ok

case 2) we have

`y=(x+3)^2+3`

This a vertical parabola open upward (the leading coefficient is positive)---> is ok

The vertex represent a minimum ---> is ok

The vertex is the point (-3,3)

The minimum value of y=3 ----> is ok

The axis of symmetry is x=-3 ----> is not ok

case 3) we have

`y=(x-3)^2-6`

This a vertical parabola open upward (the leading coefficient is positive)---> is ok

The vertex represent a minimum ---> is ok

The vertex is the point (3,-6)

The minimum value of y=-6 ----> is not ok

The axis of symmetry is x=3 ----> is ok

case 4) we have

`y=(x-3)^2+3`

This a vertical parabola open upward (the leading coefficient is positive)---> is ok

The vertex represent a minimum ---> is ok

The vertex is the point (3,3)

The minimum value of y=3 ----> is ok

The axis of symmetry is x=3 ----> is ok