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Seven times the first number plus six times the second number equals 31

1 Answer

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Final answer:

To solve this problem, you can use the given equation and isolate one of the variables to find the solution.

Step-by-step explanation:

Let's solve the equation:

7x + 6y = 31

where:

x is the first number

y is the second number

To solve for x and y, we can use the substitution method. Let's first express y in terms of x:

y = (31 - 7x) / 6

Now we can substitute this expression for y into the original equation:

7x + 6 × (31 - 7x) / 6 = 31

Simplifying the right side of the equation, we get:

7x + 31 - 7x = 31

Combining like terms, we get:

-7x + 31 = 31

Subtracting 31 from both sides, we get:

-7x = 0

Dividing both sides by -7, we get:

x = 0

Now that we know x, we can substitute it back into the expression for y:

y = (31 - 7 × 0) / 6

Simplifying, we get:

y = 31 / 6

Therefore, the two numbers are x = 0 and y = 31 / 6.

User James Logan
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