230k views
2 votes
Seven times the first number plus six times the second number equals 31

1 Answer

3 votes

Final answer:

To solve this problem, you can use the given equation and isolate one of the variables to find the solution.

Step-by-step explanation:

Let's solve the equation:

7x + 6y = 31

where:

x is the first number

y is the second number

To solve for x and y, we can use the substitution method. Let's first express y in terms of x:

y = (31 - 7x) / 6

Now we can substitute this expression for y into the original equation:

7x + 6 × (31 - 7x) / 6 = 31

Simplifying the right side of the equation, we get:

7x + 31 - 7x = 31

Combining like terms, we get:

-7x + 31 = 31

Subtracting 31 from both sides, we get:

-7x = 0

Dividing both sides by -7, we get:

x = 0

Now that we know x, we can substitute it back into the expression for y:

y = (31 - 7 × 0) / 6

Simplifying, we get:

y = 31 / 6

Therefore, the two numbers are x = 0 and y = 31 / 6.

User James Logan
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories