Question

A force of 100 N is applied to a crate at an angle of 60° to the horizontal surface.

The force causes the crate to move 2 m across the floor. How much work is done
on the crate?
50 J
100 J
2003

Answer 1

100 J

Step-by-step explanation:

Given:

Force acting on the crate is,
`F=100\ N`

Displacement of the crate is,
`S=2\ m`

Angle between the direction of force and displacement is,
`\theta=60\°`

Now, work done by a force 'F' causing a displacement 'S' such that the angle between the force and displacement is
`\theta` is given as:

`Work=F* S* \cos\theta`

Now, plug in 100 N for 'F', 2 m for 'S', and 60° for
`\theta`. This gives,

`Work=(100\ N)(2\ m)(\cos(60))\\\\Work=(200* 0.5)\ \textrm{N-m}\\\\Work=100\ J`

Therefore, the work done by the force is 100 J.