Question

The combustion of acetylene gas is represented below.

2C2H2(g) + 502(g) --> 4CO2(g) + 2H20(V)
How many moles of carbon dioxide gas were produced from 5 moles of oxygen gas?

Answer 1

Step-by-step explanation:

2C2H2 (g) + 5O2 (g) ----> 4CO2(g) + 2H20 (g)

Calculate the moles of C2H2 used

that 52g/ 26 g/mol(molar mass of C2H2)= 2moles

by of use of reacting ratio between C2H2 to CO2 which is 2 :4 therefore the moles of CO2 = 2 x4/2 = 4 moles

mass of CO2 is therefore = 4 mol x 44 g/ mol(molar mass of CO2) = 176 grams

the mole of water is calculated by use mole ratio between C2H2 to H20 which is 2:2 therefore also = 2 moles

mass of water is = 2 moles x 18 g/mol = 36grams