Question

How many grams of O2 are produced from 356.6g of Al2O3

Answer 1

168 grams of O2 are produced from 356.6g of Al2O3

Step-by-step explanation:

Calculate the moles of Al2O3

Given mass = 356.6

Molar mass of Al2O3 = 2(mass of Al) +3(mass of O)

= 2(27) + 3(16)

=102 g/mol

`mole =(given\ mass)/( Molar\ mass)`

`mole =(356.6)/(102)`

= 3.5 mole

The balanced equation for the equation is :

`4Al+3O_(2)\rightarrow 2Al_(2)O_(3)`

2 mole of Al2O3 will give 3 mole of Oxygen

1 mole of Al2O3 = 3/2 = 1.5 mole of Oxygen

3.5 mole of Al2O3 = (1.5 x 3.5 ) mole of Oxygen

3.5 mole of Al2O3 = 5.25 moles of oxygen

Use,

`given\ mass= Molar\ mass* moles`

Molar mass of O2 = 16(2) = 32 g/mol

`given\ mass= 32* 5.25`

= 168 g