Answer:
The four compounds with formula C4H9Br are
1. 1- Bromobutane
2. 2-Bromobutane
3. 1-bromo-2-methyl propane
4. 2-Bromo-2-methyl propane
Reactivity towards SN2 in decreasing order is :
1- Bromobutane > 1-bromo-2-methyl propane > 2-Bromobutane >
2-Bromo-2-methyl propane
Step-by-step explanation:
SN2 reaction : This is also known as second order nucleophilic Substitution Reaction because :
- The rate determining step depends both on the concentration of the substrate as well as nucleophile.
- This reaction involve formation of 5- bond transition state (not the intermediate)
- The bond making and breaking occur simultaneously
- The reactivitey order for SN2 is more for less hindered substrate i.e :
Primary > Secondary > tertiary
Among the isomers of C4H9Br
- The primary halides are : 1- Bromobutane and 1-bromo-2-methyl propane
(Br is attached to primary carbon)
but 1- Bromobutane is less hindered than 1-bromo-2-methyl propane
So,1- Bromobutane > 1-bromo-2-methyl propane
- Tertiary : 2-Bromo-2-methyl propane
Hence order is :
1- Bromobutane > 1-bromo-2-methyl propane > 2-Bromobutane >
2-Bromo-2-methyl propane