Question

A gas cylinder contains 2.50X103g of O2 (g)in

a volume of 10.0L. What pressure is exerted by the Oxygen at20.0
oC?

Answer 1

188 atm

Step-by-step explanation:

Given data

• Mass of O₂ (m): 2.50 × 10³ g

• Volume (V): 10.0 L

• Temperature (T): 20.0°C + 273.15 = 293.2 K

The molar mass of O₂ is 32.00 g/mol. The moles of O₂ are:

2.50 × 10³ g × (1 mol/ 32.00 g) = 78.1 mol

We can find the pressure exerted by the oxygen using the ideal gas equation.

P × V = n × R × T

P = n × R × T / V

P = 78.1 mol × (0.0821 atm.L/mol.K) × 293.2 K / 10.0 L

P = 188 atm