Question

How many atoms of iron are in 0.750 moles of the compound
Iron(III) oxide?

Answer 1

The empirical formula of Iron(III) oxide is Fe2O3, which means there are two atoms of iron and three atoms of oxygen in the compound.

Step-by-step explanation:

The empirical formula of Iron(III) oxide is Fe2O3, which means there are two atoms of iron (Fe) and three atoms of oxygen (O) in the compound. The ratio between iron and oxygen in the compound is 2:3.

Answer 2

2.26 × 10²⁴ atoms

Step-by-step explanation:

In 1 mole of Fe₂O₃ (Iron(III) oxide), there are 6.02 × 10²³ molecules of Fe₂O₃ (Avogadro's number). The molecules of Fe₂O₃ in 0.750 moles are:

0.750 mol × (6.02 × 10²³ molecules/ 1 mol) = 4.52 × 10²³ molecules

In 1 molecule of Fe₂O₃, there are 5 atoms (2 atoms of Fe and 3 atoms of O). The atoms in 4.52 × 10²³ molecules of Fe₂O₃ are:

4.52 × 10²³ molecule × (5 atom/1 molecule) = 2.26 × 10²⁴ atom

There are 2.26 × 10²⁴ atoms in 0.750 moles of Fe₂O₃.