Question

Balance the equation below and use it to answer thefollowing

questions.


C4H10 + O2 ==> CO2
+H2O


How many moles of oxygen are needed to react with 54.7 g
ofbutane?

Answer 1

6.12 mol

Step-by-step explanation:

Let's consider the following balanced equation.

C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O

We can establish the following relations.

• The molar mass of butane is 58.12 g/mol.
• The molar ratio of butane to oxygen is 1:6.5.

The moles of oxygen needed to react with 54.7 g of butane are:

`54.7gButane.(1molButane)/(58.12gButane).(6.5molOxygen)/(1molButane) =6.12molOxygen`