Question

A 35.00ml sample of NaOH solution is titrated to an endpointby

14.76 ml 0.4122M HBr solution. What is the molarity of themolarity
of the NaOh solution.

Answer 1

0.1738 M

Step-by-step explanation:

Let's consider the neutralization reaction between NaOH and HBr.

NaOH + HBr → NaBr + H₂O

The moles of HBr are:

14.76 × 10⁻³ L × 0.4122 mol/L = 6.084 × 10⁻³ mol

The molar ratio of NaOH to HBr is 1:1. In the endpoint, they have reacted completely, so the moles of NaOH were 6.084 × 10⁻³ mol before the reaction.

The molarity of NaOH is:

M = 6.084 × 10⁻³ mol / 35.00 × 10⁻³ L = 0.1738 M