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4 votes
Caluclate the number of grams of oxygen that must react

with46.85g of C3H 8 to produce only carbondioxide
and water.

User TheFastCat
by
8.3k points

1 Answer

1 vote

Answer : The number of grams of oxygen react must be, 170.4 grams.

Solution : Given,

Mass of
C_3H_8 = 46.85 g

Molar mass of
C_3H_8 = 44 g/mole

Molar mass of
O_2 = 32 g/mole

First we have to calculate the moles of
C_3H_8.


\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=(46.85g)/(44g/mole)=1.065moles

Now we have to calculate the moles of
O_2

The balanced chemical reaction is,


C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

From the balanced reaction we conclude that

As, 1 mole of
C_3H_8 react with 5 mole of
O_2

So, 1.065 moles of
C_3H_8 react with
1.065* 5=5.325 moles of
O_2

Now we have to calculate the mass of
O_2


\text{ Mass of }O_2=\text{ Moles of }O_2* \text{ Molar mass of }O_2


\text{ Mass of }O_2=(5.325moles)* (32g/mole)=170.4g

Therefore, the number of grams of oxygen react must be, 170.4 grams.

User Shafeeq
by
8.3k points
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