Question

What volume of .10 M NaOH can be prepared from 250 mL of .30
MNaOH?

Answer 1

750 mL

Step-by-step explanation:

Given data

• Initial concentration (C₁): 0.30 M

• Initial volume (V₁): 250 mL

• Final concentration (C₂): 0.10 M

• Final volume (V₂): to be found

We can determine the volume of the diluted solution to be prepared by using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₂ = C₁ × V₁ / C₂

V₂ = 0.30 M × 250 mL / 0.10 M

V₂ = 750 mL