A sample of gas occupies 250 mL under laboratory conditions of27oC and 740 mmHg pressure. What is the volume atstandard temperature and pressure conditions?

Question

asked Dec 25, 2021 222k views

1 Answer

Isidro · Answer 1 · 2021-12-31T00:56:46+0000

Answer : The volume at standard temperature and pressure conditions is, 222 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

(P_1V_1)/(T_1)=(P_2V_2)/(T_2)

where,

P_1 = initial pressure of gas = 740 mmHg

P_2 = final pressure of gas = 760 mmHg

V_1 = initial volume of gas = 250 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas =
27^oC=273+27=300K

T_2 = final temperature of gas =
0^oC=273+0=273K

Now put all the given values in the above equation, we get:

(740mmHg* 250mL)/(300K)=(760mmHg* V_2)/(273K)

$V_2=221.5\approx 222mL$

Therefore, the volume at standard temperature and pressure conditions is, 222 mL