Question

If oxygen were collected over water at 293 K and the

totalpressure of the wet gas were 670 mmHg, what would be the
partialpressure of the oxygen?

Answer 1

652 mmHg

Step-by-step explanation:

Given data

• Total pressure (P): 670 mmHg

• Temperature (T): 293 K

• Vapor pressure of water at 293 K (Pwater): 17.54 mmHg

When oxygen is collected over water, the total pressure is the sum of the partial pressures of oxygen and water vapor at the given temperature.

P = Poxygen + Pwater

Poxygen = P - Pwater

Poxygen = 670 mmHg - 17.54 mmHg

Poxygen = 652 mmHg