Question

Determine the oxidation number for nitrogenin

each of the following
a. NO2 1-
b. N2
c. NO2Cl
D. N2H4
2. Benzene is a common hydrocarbon,whic his widely used as a
solvent.
From another experiment, the molecular mass of benzene
wasdetermined to be 78.0 grams per mole. What is the
molecularformular for benzene?

Answer 1

1(a) N = 3

(b) N = 0

(c) N = 5

(d) N = -2

(2) Molecular formula for benzene is C6H6

Step-by-step explanation:

1(a) N02 1-

N + (2×-2) = -1

N-4 = -1

N = -1+4 = 3

(b) N2

2(N) = 0

N = 0/2 = 0

(c) NO2Cl

N + ( 2×-2) + (-1) = 0

N - 4 - 1 = 0

N - 5 = 0

N = 0+5 = 5

(d) N2H4

2(N) + (4×1) = 0

2N + 4 = 0

2N = 0 - 4 = -4

N = -4/2 = -2

(2) Molcular mass of benzene = 78g/mole = (6×12g of carbon) + (6×1g of hydrogen) = 72+6 = 78g/mole

Therefore, molecular formula for benzene is C6H6