Answer:
a) 0.02275
b) 0.4515
Explanation:
Data provided in the question:
Mean = 500
Standard deviation, s = 100
Now,
a) More than 700
z score = [ X - mean ] ÷ s
= [700 - 500 ] ÷ 100
= 2
P(More than 700) = P(z > 2 )
or
P(More than 700) = 0.02275 [ from standard z vs P table ]
b) Between 440 and 560
z score for X = 440
= [440 - 500 ] ÷ 100
= - 0.6
z score for X = 560
= [560 - 500 ] ÷ 100
= 0.6
Now,
P( Between 440 and 560 ) = P (z < 0.6 ) - P( z < -0.6 )
thus,
P( Between 440 and 560 ) = 0.7257469 - 0.2742531
= 0.4515