Question

A group of 10 fisherman enjoy certain types of fish, 3 of them like salmon, 5 like trout and 2 like bass. A single fisherman is chosen at random. What is the probability that the fisherman likes salmon or bass?

Answer 1

`P(salmon or bass)=(1)/(2)`

Explanation:

A group of 10 fisherman enjoy certain types of fish, 3 of them like salmon, 5 like trout and 2 like bass.

P(event)= number of outcomes divide by total outcomes

`P(salmon)=(3)/(10)`

`P(bass)=(2)/(10)=(1)/(5)`

`P(salmon or bass)=(3)/(10)+(2)/(10)=(5)/(10)=(1)/(2)`