Question

A pocket of gas is discovered in a deep drilling operation.The

gas has a temperature of 480 degrees celsius and is at a pressure
of 12.8 atm. What volume of gas is required toprovide 18.01L of gas
at the surface where the conditions are 22degrees celsius and
1.00atm?

Answer 1

Answer : The volume of gas required to provide 18.01L of gas at the surface is, 3.6 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 12.8 atm

`P_2` = final pressure of gas = 1.0 atm

`V_1` = initial volume of gas = ?

`V_2` = final volume of gas = 18.01 L

`T_1` = initial temperature of gas =
`480^oC=273+480=753K`

`T_2` = final temperature of gas =
`22^oC=273+22=295K`

Now put all the given values in the above equation, we get:

`(12.8atm* V_1)/(753K)=(1.0atm* 18.01L)/(295K)`

`V_1=3.59L\approx 3.6L`

Therefore, the volume of gas required to provide 18.01L of gas at the surface is, 3.6 L