Answer : The mass of NaCl added should be, 5.85 grams.
Explanation : Given,
Mass of
= 250 g
Molality of solution = 0.40 mol/kg
Molar mass of
= 58.5 g/mole
Molality : It is defined as the number of moles of solute present in one kilogram of solvent.
Formula used :
![\text{Molality}=\frac{\text{Mass of NaCl}* 1000}{\text{Molar mass of NaCl}* \text{Mass of water (in g)}}](https://img.qammunity.org/2021/formulas/chemistry/college/gudl9yw2b3lkzmtii6gqz32h56x9karnsk.png)
Now put all the given values in this formula, we get:
![0.40mol/kg=\frac{\text{Mass of NaCl}* 1000}{58.5g/mole* 250g}](https://img.qammunity.org/2021/formulas/chemistry/college/p0pupmo251e983yxvqu7egynzhwkaxq1tq.png)
![\text{Mass of NaCl}=5.85g](https://img.qammunity.org/2021/formulas/chemistry/college/df2k032pohcy9xon7nqyfldtzd2zi5kcho.png)
Therefore, the mass of NaCl added should be, 5.85 grams.