Answer: If we throw 4 cubes, there are 1296 different outcomes are possible.
Explanation:
Given : A cube has faces numbered 1 to 6.
So the number of outcomes for throwing one die = 6
If we throw 4 cubes , then
According to the Fundamental counting principle,
The total number of different outcomes are possible =
![(\text{Number of outcomes for throwing one die})^4](https://img.qammunity.org/2021/formulas/mathematics/high-school/x2ilykht3a2jno10ch8qwodq6664dv7hq0.png)
Therefore , The total number of different outcomes are possible
![=6^4=1296](https://img.qammunity.org/2021/formulas/mathematics/high-school/n7tyrdbhrrd4cm5yerlh1ivqkwanjfmovp.png)
Hence, there are 1296 different outcomes are possible.