Question

A car goes around a curve of radius r at a constant speed v. Then it goes around a curve of radius 2r at speed 2v. What is the centripetal acceleration on the car as it goes around the second curve, compared to the first?

Answer 1

Answer:2v^2/r

Step-by-step explanation:

Answer 2

`a'=2* a`

Step-by-step explanation:

given,

first case

car speed = v

radius of curve = r

second case

car speed (v')= 2 v

radius of curve (r')=2 r

centripetal acceleration of car is given by

`a=(v^2)/(r)`

for second case

`a'=(v'^2)/(r')`

`a'=((2v)^2)/(2r)`

`a'=2(v^2)/(r)`

`a'=2* a`

Hence, the centripetal acceleration on the second case is twice of first case.