Hi there, your question was incomplete, so I will be solving a similar question so it would help you to understand how to answer these types of questions
Q) A chemist must dilute 22.5mL of 119μ M aqueous silver(II) oxide AgO solution until the concentration falls to 65.0μ M . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Round your answer to significant digits.
Answer:
Final Volume V2 = 41.2 mL
Step-by-step explanation:
We will start by first recalling the formula of dilution which goes by,
M1 * V1 = M2 * V2 ------------------------------(1)
Now let us consider V1 = 22.5 mL
M1 = 119μ M
M2 = 65.0μ M
lets substitute the values above in equation 1,
M1 * V1 = M2 * V2
V2 = (M1 * V1)/M2 ( I have created V2 as the subject here)
V2 = (119*22.5)/65
V2 = 41.2 mL