Answer:
The quadrilateral is not a parallelogram
Explanation:
we know that
In a parallelogram opposite sides are parallel and congruent
Find the length of the sides of the quadrilateral
step 1
Find the distance QR
the formula to calculate the distance between two points is equal to
![d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/k8w8jf3efjehwebwzmarl4rkh1hj6b20u3.png)
we have
Q(-10,-2), R(1,-1)
substitute
![d=\sqrt{(-1+2)^(2)+(1+10)^(2)}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/hw7he7jqp1zmcue5949o8to1ago3vfv257.png)
![d=\sqrt{(1)^(2)+(11)^(2)}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yhd4ysjqfatncjzdyv8609903ke3skhkts.png)
![d=√(122)\ units](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vlam773g8fuscffsmtiuhjlfqsyhzqmra4.png)
step 2
Find the distance TS
the formula to calculate the distance between two points is equal to
![d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/k8w8jf3efjehwebwzmarl4rkh1hj6b20u3.png)
we have
T(-11,-8), S(1,-7)
substitute
![d=\sqrt{(-7+8)^(2)+(1+11)^(2)}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ylu6vprwadai3fty6b68x8y0zarmtdohh4.png)
![d=\sqrt{(1)^(2)+(12)^(2)}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7liqj7ny2xsj9wkie5icvdg4zoirb4ha9d.png)
![d=√(145)\ units](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qrj38r0896159lbdfj0cwkxp80iw37bdi8.png)
we have that
QR and TS are opposite sides
In a parallelogram opposite sides are congruent but in this problem
![QR \\eq TS](https://img.qammunity.org/2021/formulas/mathematics/middle-school/14ypov007w2nte9mulwdkj73fvdhe4jwo6.png)
![√(122)\ units \\eq √(145)\ units](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jt3g3pmeygd9gwkwniwz1a4rpmwkk6be0d.png)
therefore
The quadrilateral is not a parallelogram