Question

At target prctice, Scott holds his bow and pulls the arrowback

a distance of 0.30m by exerting an average force of 40.00Nwhat is
the potential energy stored in the bow the moment beforethe arrow
is released?

Answer 1

The potential energy stored in the bow before the arrow is released can be calculated using the formula PE = (1/2) k x^2, where PE is the potential energy, k is the spring constant of the bow, and x is the distance the bow is pulled back. However, the specific potential energy value cannot be calculated without the spring constant.

Step-by-step explanation:

The potential energy stored in the bow before the arrow is released can be calculated using the formula:

PE = (1/2) k x^2

where PE is the potential energy, k is the spring constant of the bow, and x is the distance the bow is pulled back. In this case, the distance pulled back is 0.30m and the average force exerted is 40.00N. However, the provided information does not include the spring constant of the bow, so we cannot calculate the specific potential energy value.

Answer 2

The notion of potential energy is related to the work done by the forces on the physical system to move it from one position to another in space. That is to say in practical terms it can be calculated by the Force applied in a certain distance. Mathematically this is

`PE = W = F*d`

Here,

PE = Potential Energy

W= Work

F = Force

d = Distance

Replacing we have,

`PE = 40*0.3`

`PE = 12J`

Therefore the potential energy stored in the bow the moment before the arrow is released is 12J.