Question

Marisa does 3.2J of work to lower the window shade in

herbedroom a distance of 8.0m. How much force must Marissa exert
onthe window shade?

Answer 1

Work is considered as the Force performed on a body to move it a certain distance, that is

W = Fd

Here

W = Work

F = Force

d = Distance

In this case we have the values of work and distance, therefore clearing for the Force we would have to

`F = (W)/(d)`

Replacing,

`F = (3.2J)/(8m)`

`F = 0.4N`

Therefore the force that Marissa must exert on the windows shade is 0.4N