Question

How much total kinetic energy will an electron-position

pairhave if produced by a photon of energy 3.24 MeV?

Answer 1

Answer:2.2 MeV

Step-by-step explanation:

Given

Energy of incoming Photo
`E=3.24 MeV`

and Rest mass of electron and Proton has 0.51 Mev which can be derived by

mass of Electron
`m=9.11* 10^(-31)\ kg\approx (0.51)/(c^2)\ MeV`

Where
`c=velocity\ of\ light`

Energy associated
`E=(0.51)/(c^2)* c^2=0.51 MeV`

This energy can be treated as work function i.e.

Work function
`W=2* 0.51=1.02\ MeV`

Applying Einstein Equation we get

`E=W+K.E.`

`K.E.=3.24-1.02=2.2 MeV`