Answer:
![v_2=3.2\ m/s](https://img.qammunity.org/2021/formulas/physics/college/617lppwnbn0iozf845lv5bo0lahgjt7kom.png)
Step-by-step explanation:
given,
diameter of inlet = 11.2 cm
r₁ = 5.6 cm
r₁ = 0.056 m ∵ 1 cm = 0.01 m
speed of inlet = 5 m/s
diameter of outlet = 17.5 cm
r₂ = 8.75 cm
r₂ = 0.0875 m ∵ 1 cm = 0.01 m
speed of outlet = ?
using continuity equation
A₁ v₁ = A₂ v₂
π r₁² v₁ = π r₂² v₂
![v_2= 0.64 v_1](https://img.qammunity.org/2021/formulas/physics/college/x6b15zow41wt19by1jtlhy9tfl29uy1j69.png)
![v_2= 0.64* 5](https://img.qammunity.org/2021/formulas/physics/college/a61m7y4s0e07rnxjmt380wxryeaytpxkai.png)
![v_2=3.2\ m/s](https://img.qammunity.org/2021/formulas/physics/college/617lppwnbn0iozf845lv5bo0lahgjt7kom.png)
Velocity of liquid at the outlet of the tube is equal to 3.2 m/s