Question

A block lies on a horizontal frictionless surface and

isattached to the free end of a spring, with a spring constant of
60N/m. Initially, the spring is at its relaxed length and the
blockis stationary at position x = 0. Then an applied force with
aconstant magnitude of 3 N pulls the block in the positive
directionof the x axis, stretching the spring until the block
stops. Assumethat the stopping point is reached. What is the
position of theblock?

Answer 1

0.1 m

Step-by-step explanation:

F = Force exerted on spring = 3 N

k = Spring constant = 60 N/m

x = Displacement of the block

As the energy of the system is conserved we have

`Fx=(1)/(2)kx^2`

`\\\Rightarrow x=(2F)/(k)`

`\\\Rightarrow x=(2* 3)/(60)`

`\\\Rightarrow x=0.1\ m`

The position of the block is 0.1 from the initial position.