Question

An archer's bow is drawn at its midpoint until the tension

inthe string is 1.20 times the force exerted by the archer. What
isthe angle between the two halves of the string?

Answer 1

θ= 131° and in radian rad = 2.27

Step-by-step explanation:

We have find the angle as the tension in the string is 1.20 times the force.

as We have

F = 2.T.cos(θ/2)

Angle can be found as

θ = 2×cos⁻¹(1/(1.2×2))......................2 times because angle between the two halves of the string

θ= 131° and in radian rad = 2.27