Question

Y=5x+2
4x-y=0
is (2,12) a solution of the system?

Answer 1

The point (2,12) satisfies the first equation y=5x+2, but it does not satisfy the second equation 4x-y=0. Therefore, it is not a solution to the system of equations.

Step-by-step explanation:

To determine if the point (2,12) is a solution to the system of equations y=5x+2 and 4x-y=0, we can substitute the x and y values of the point into each equation to see if they satisfy both equations simultaneously.

For the first equation, substituting x=2 gives us y=5(2)+2, which simplifies to y=10+2, and hence y=12. This matches the y-value of our point, so (2,12) satisfies the first equation.

For the second equation, 4x-y=0, substituting x=2 and y=12 gives us 4(2)-12=0, which simplifies to 8-12=0, and hence -4=0, which is not true. Therefore, (2,12) does not satisfy the second equation.

Since (2,12) does not satisfy both equations, it is not a solution to the system.

Answer 2

No

Step-by-step explanation:

For a point to be a solution of a system of equations, it has to work for both equations in said system. For this particular point, it doesn't fit into both.

12=5(2)+2

12=10+2

12=12

4(2)-12=0

8-12=0

-4=0

The second equation doesn't work out.