Answer:
3.80 m/s
Step-by-step explanation:
Solution: From the question we have:
A 2.10 x 10^3 kg car starts from rest at the top of a 5.0 m long driveway that is sloped at 20 degrees with the horizontal.
average friction force of 4.0 x 10^3 N impedes the motion
To find out: find the speed of the car at the bottom of the driveway.
=>h = 5×sin20 = 1.71 m.
PE = mgh = 2100×9.8×1.71 = 35,192 J.
KE = PE-work done by frictional force
KE=PE-4000×5
0.5mV^2 = 35192 - 4000×5
1050V^2 = 15,192
V^2 = 14.47
V = 3.80 m/s.