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A person who weighs 509,45 N empties her lungs as much as

possible and is then completely immersed in water (of density 1 000
kg/m3) while suspended from a harness. Her apparent weight is now
22,34 N. What is her density? Answer in two decimal places.

User Khaalid
by
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1 Answer

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Answer:

The weight of the girl = 1045.86 kg/m³

Step-by-step explanation:

Density: This can be defined as the ratio of the mass of a body to the volume of that body. The S.I unit of density is kg/m³.

From Archimedes principle,

R.d = Density of the person/Density of water = Weight of the person in air/Upthrust.

D₁/D₂ = W/U............................... Equation 1.

Where D₁ = Density of the person, D₂ = Density of water, W = Weight of the person in air, U = Upthrust in water.

Making D₁ the subject of the equation,

D₁ = D₂(W/U)................................... Equation 2

Given: D₂ = 1000 kg/m³ , W = 509.45 N, U = lost in weight = weight in air - weight in water = 509.45 - 22.34 = 487.11 N

Substituting these values into equation 2

D₁ = 1000(509.45/487.11)

D₁ = 1045.86 kg/m³

Thus the weight of the girl = 1045.86 kg/m³

User SammyK
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