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A disgruntled autoworker pushes a small foreign import off

acliff with a height of h. the vehicle lands a distance away
fromthe cliff. Determine how fast the vehicle was pushed off
thecliff.

User Beauty
by
4.5k points

1 Answer

3 votes

Answer:

v = a/√(2h/g) m/s

Step-by-step explanation:

Lets say the distance away from the cliff is a.

then, a = v t

where v is velocity with which it was thrown and t is time taken to fall.

Using equations of motion, we can also say that

h=1/2gt^2

where h is the height of the cliff

Thus, t^2 = 2h/g and t = √(2h/g)

Thus, v = a/√(2h/g).

the vehicle was pushed off the cliff with the velocity , v = a/√(2h/g). m/s

User Pedrotorres
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