Question

A woman is standing in the ocean, and she notices that after

awave crest passes by, five more crests pass in a time of 54.0
s.The distance between two successive crests is 39.257883151578
m.What is the wave's (a) period, (b) frequency, (c) wavelength,
and(d) speed?

Answer 1

Period, T = 10.86 seconds

Frequency, f = 0.092 Hz

Wavelength,
`\lambda=39.257883151578\ m`

Speed, v = 3.61 m/s

Step-by-step explanation:

It is given that,

A woman notices that a wave crest passes by, five more crests pass in a time of 54.0 .

The distance between two successive crests is, the wavelength of wave,
`\lambda=39.257883151578\ m`

(b)Frequency of a wave is given by number of oscillations per second such that,

`f=(n)/(t)`

`f=(5)/(54)`

f = 0.092 Hz

(a) Let T is the period of the wave. It is inverse of frequency of a wave such that,

`T=(1)/(f)`

`T=(1)/(0.092)`

T = 10.86 seconds

(c) The distance between two successive crest or trough is called wavelength of a wave,
`\lambda=39.257883151578\ m`.

(d) The speed of a wave is given by :

`v=f\lambda`

`v=0.092* 39.257883151578`

v = 3.61 m/s

Hence, this is the required solution.