Question

Two 1 MHz radio antennas emitting in-phase are separated by600

m along a north-south line. a radio reciever placed 2 kmeast is
equidistant from both transmitting antennas and picks up afairly
strong signal. How far north should that receiver bemoved if it is
again to detect a signal nearly as strong?

Answer 1

1 km

Step-by-step explanation:

`d_0` = Gap between antennas = 600 m

`\\u` = Frequency = 1 MHz

`z_1` = Distance to receiver = 2 km

c = Speed of light =
`3* 10^8\ m/s`

Wavelength is given by

`\lambda=(c)/(\\u)\\\Rightarrow \lambda=(3* 10^8)/(1* 10^6)\\\Rightarrow \lambda=300\ m`

Distance to be moved is given by

`D=(z_1\lambda_0)/(d_0)\\\Rightarrow D=(2* 300)/(600)\\\Rightarrow D=1\ km`

The distance to be moved is 1 km north.