Question

2. Discuss how you might select a random sample to estimate the population mean rating of all 100 computer games.

Answer 1

`n = (NZ^(2)_(1-\alpha/2)\sigma^(2))/(E^(2)(N-1)+Z^(2)_(1-\alpha/2)\sigma^(2))`

Explanation:

For calculating how large is a sample size that is large enough for estimating the population mean, we should consider the error that we are ready to agree, because the sample size depends on this error.

If your error is α, the sample size would be:

`n = (NZ^(2)_(1-\alpha/2)\sigma^(2))/(E^(2)(N-1)+Z^(2)_(1-\alpha/2)\sigma^(2))`

Where N: the population size, in your case N = 100

δ: the standar deviation

Z: the value associated to the error in the standard normal table

E: error