Question

Two parallel wires have a current of 22A flowing through each oneof

them. when the wires are placed 25cm apart, the exert a force
of2.7x10-4N on each other. find the length of the wires.

Answer 1

The length of both the wires is 69 cm

Step-by-step explanation:

It is given that,

Current flowing in each wire,
`I_1=I_2=22\ A`

Distance between wires, d = 25 cm = 0.25 m

Force exerted on each wire,
`F=2.7* 10^(-4)\ N`

The force per unit length between two parallel wires carrying current is given by :

`(F)/(l)=(\mu_oI_1I_2)/(2\pi d)`

l is the length of the wires

`l=(2\pi dF)/(\mu_oI_1I_2)`

`l=(2\pi * 0.25* 2.7* 10^(-4))/(4\pi * 10^(-7)* (22)^2)`

`l=0.69\ m`

or

l = 69 cm

So, the length of both the wires is 69 cm. Hence, this is the required solution.