Question

What is the mass of 1.63 moles and f ammonium phosphorus (NH4)3PO4

Answer 1

mass (NH4)3PO4 = 243.011 g

Step-by-step explanation:

mass (NH4)3PO4 = ?

∴ moles (NH4)3PO4 = 1.63 moles

∴ molecular weight (Mw) = 149.0867 g/mol

• mass = (mol)×(Mw)

⇒ mass (NH4)3PO4 = ( 1.63 mol (NH4)3PO4 )×( 149.0867 g/mol )

⇒ mass (NH4)3PO4 = 243.011 g